Question

find the zeroes of the quadratic polynomial and verify the relationship between the zeroes and the cofficient 6x2-3-7x

Answer 1

Question :- 6x²-7x-3

=6x²+2x-9x-3

=2x(3x+1)-3(3x+1)

=(2x-3)(3x+1) = Zeroes !!

⇒2x-3=0                          

         or                          

 ⇒3x+1=0

⇒x=3/2                        ------(1)

  or                           

⇒ x= - 1/3 ------(2)

Verification :-

α=3/2 ,β= - 1/3

✌α+β= -b/a

⇒3/2+(-1/3)= - (-3)/6

⇒3/2-1/3=1/2

⇒7/6 =1/2

 ✌ αβ=c/a

 ⇒ 3/2(-1/3)= -7/6

⇒-1/2= -7/6

 ⇒1/2=7/6      

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