find the zeroes of the quadratic polynomial f(x)=abx2+(b2-ac)x-bc and verify the relationship between zeroes and its cofficients
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Abx2+b2x-acx-bc=0
Bx(ax+b)-c(ax+b)=0
(ax+b) (bx-c) =0
X=-b/a,x=c/b=0
Hope it's help you friend ☺️
Bx(ax+b)-c(ax+b)=0
(ax+b) (bx-c) =0
X=-b/a,x=c/b=0
Hope it's help you friend ☺️
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