Math, asked by eswarkumar5588, 1 year ago

find the zeroes of the quadratic polynomial f(x)=abx2+(b2-ac)x-bc

Answers

Answered by conjureroman
8
Hey dear friend

=>abx²+(b²-ac)x-bc

By mid term splitting

=>abx²+b²x-acx-bc=0

=>bx(ax+b) -c(ax+b)=0

=>(bx-c)(ax+b)=0

Taking (bx-c)=0

=>bx-c=0
=>bx=c
=>x=c/b

Taking (ax+b)=0

=>(ax+b)=0
=>ax= -b
=>x= -b/a

So the zeroes of given equation are
1. c/b
2. -b/a

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