find the zeroes of the quadratic polynomial f(x)=abx2+(b2-ac)x-bc
Answers
Answered by
8
Hey dear friend
=>abx²+(b²-ac)x-bc
By mid term splitting
=>abx²+b²x-acx-bc=0
=>bx(ax+b) -c(ax+b)=0
=>(bx-c)(ax+b)=0
Taking (bx-c)=0
=>bx-c=0
=>bx=c
=>x=c/b
Taking (ax+b)=0
=>(ax+b)=0
=>ax= -b
=>x= -b/a
So the zeroes of given equation are
1. c/b
2. -b/a
Be PERFECTIONIST
hope it helps you mark me as brainliest and follow me
=>abx²+(b²-ac)x-bc
By mid term splitting
=>abx²+b²x-acx-bc=0
=>bx(ax+b) -c(ax+b)=0
=>(bx-c)(ax+b)=0
Taking (bx-c)=0
=>bx-c=0
=>bx=c
=>x=c/b
Taking (ax+b)=0
=>(ax+b)=0
=>ax= -b
=>x= -b/a
So the zeroes of given equation are
1. c/b
2. -b/a
Be PERFECTIONIST
hope it helps you mark me as brainliest and follow me
Similar questions