Question

find the zeroes of the quadratic polynomial
f(x) = abx2 +(b2 - ac) x-bc
and veriy the relationship between the
zeros and its cofficients.
​

Answer 1

answer. this is right....

Answer 2

The zeroes of the quadratic polynomial are -b/a and c/b

Step-by-step explanation:

Given

$f(x)=abx^2+(b^2-ac)x-bc$

In order to find the zeroes of f(x)

$f(x)=0$

$\implies abx^2+(b^2-ac)x-bc=0$

or, $abx^2+b^2x-acx-bc=0$

or, $bx(ax+b)-c(ax+b)=0$

or, $(ax+b)(bx-c)=0$

$\impies x=-\frac{b}{a}, x=\frac{c}{b}$

Hope this answer is helpful.

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