Question

find the zeroes of the quadratic polynomial f (x) = x 2 - 3 x - 28 and verify the relationship between the zeroes and the coefficients of the polynomial. ( 2012,2017D)​

Answer 1

Answer:

Step-by-step explanation:

x^2-3x-28=f(x)

x^2-7x+4x-28=0

x(x-7)+4(x-7)=0

(x+4)(x-7)=0

x=-4 and x=7(zeros)

-b/a=-(-3)/1=3                  alpha+beta(sum of zeros)=-4+7=3

as LHS =RHS HENCE PROVED

c/a=-28/1=-28           alpha*beta=-4*7=-28

as lhs =rhs hence verified