Question

Find the zeroes of the quadratic polynomial f (x)=x2-3x-28 and verify the relationship between the zeroes and the co-efficients of the polynomial

Answer 1

f(x) = x^2-3x-28

x^2-3x-28=0

x^2-7x+4x-28=0

x(x-7) + 4(x-7) =0

(x-7)(x+4)=0

x=7 or x=-4

roots of the polynomial= 7, -4

sum of roots= -b/a

7+(-4) = -(-3)/1

3 = 3

product of roots= c/a

7(-4) = -28/1

-28=-28

hence verified

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