Find the zeroes of the quadratic polynomial
(i) p(x) = 5x2 + 4x
(ii) p(x) =9x2 + 6x + 1
(iii) p(x) 6x2 + x -12
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The first answer is of 5x2 + 4x is 0
The second answer is 9x2 +6x + 1 is 16
The third answer is 6x2 +x -12 is -7
The second answer is 9x2 +6x + 1 is 16
The third answer is 6x2 +x -12 is -7
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