Question

find the zeroes of the quadratic polynomial p(×)=6×2-3-7×.​

Answer 1

Answer:

3/2 & -1/3

Step-by-step explanation:

6x^2-3-7x

6x^2-7x-3

6x^2-9x+2x-3

(6x^2-9x)+(2x-3)

3x(2x-3)+1(2x-3)

(2x-3)(3x+1)

So, 2x-3=0 & 3x+1=0

x=3/2 & x=-1/3

Hence, the zeroes of p(x) are 3/2 and -1/2.

Hope it will help you!