find the zeroes of the quadratic polynomial p(x)=3x²-5x-2?
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Step-by-step explanation:
p(x) = 3x² - 6x + x - 2
put p(x) = 0 and solve for 'x'
3x² - 6x + x - 2 = 0
=> 3x (x - 2) + 1 (x - 2) = 0
=> (x - 2) (3x+ 1) = 0
=> x - 2 = 0 and 3x + 1 = 0
=> x = 2 and x = - 1/3
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