Find the zeroes of the quadratic
polynomial p(x) = 6x² - 13 -7
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Answer:
Step-by-step explanation:
p(x)=6x²-13-7
6x²-7x-6x-7=0
(6x²-7x)-(6x-7)
x(6x-7)-1(6x-7)
(x-1) (6x-7)
x= 1, x= 7/6
hope it helps you!!
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