Question

Find the zeroes of the quadratic polynomial, p(x) = 6x2 + 18x, and verify the relationship between the zeroes and the coefficients.

Answer 1

given 6x^2+18x=0

6x(x+3)=0

x=0 and x=-3

sum of roots =-3

product =0

from coefficient a=6,b=18,c=0

sum of roots =-b/a=-18/6=-3

product =c/a=0

Answer 2

Answer:

See below

Step-by-step explanation:

6x²+18x=0

so 6x(x+3)=0

x+3 =0

x= -3 (1)

then just understand that when an equation is given without C then one of its zeros are 0

so 0 (2)

-18 , 0 are the two zeros

proof

-b/a = -18/6 = -3   .1

6/0 = 0      .2

done