Question

Find the zeroes
of the quadratic polynomial
p(x) 6x2 -3-7x​

Answer 1

Step-by-step explanation:

Given, the polynomial 

6x2−13x+6=0⇒6x2−9x−4x+6=0⇒3x(2x−3)−2(3x−3)=0⇒(2x−3)(3x−2)=0∴2x−3=0⇒x=233x−2=0⇒x=32

Let, α=23,β=32

From the polynomial we get, a=6,b=−13,c=6

∴ Relation between the zeroes and coefficients,

Sum of the zeroes=23+32=613=−6(−13)=ab

and product of the zeroes=23×32=66=a