Question

Find the zeroes of the quadratic polynomial P(x) = 6x² - x-12. Verify the
relationship between zeroes
and coefficient.
quadratic nolunomi
Forma quadratie​

Answer 1

Answer:

6x2-x-12=0

6x2-9x+8x-12=0

3x(2x-3)+4(2x-3)=0

(3x+4)(2x-3)=0

x=-4/3 or x=3/2

sum of zeros = 3/2+(-4)3) =1/6

product of zeros = (3/2)(-4/3)=-12/6 =-2

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