Math, asked by pkhushbu1705, 1 month ago

Find the zeroes of the quadratic polynomial p(x) = ab x² + (b² - ac) x - b

Answers

Answered by Anonymous
4

Step-by-step explanation:

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Answered by darksoul3
13

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a = ab

b = (b² - ac)

c = b

The zeroes are

Sum of zeroes = α + β =  \frac{ - b}{a} =  \frac{( {b}^{2}   - ac)}{ab}

Product of zeroes = αβ =  \frac{c}{a} =

 \frac{b}{ab} =  \frac{1}{a}

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