Question

find the zeroes of the quadratic polynomial p(x)= xsqaure +x-12 And verify the relationship between the zeroes and the coefficients​

Answer 1

Step-by-step explanation:

$x {}^{2} + x - 12 = x {}^{2} + 4x - 3x - 12 \\ x(x + 4) - 3(x + 4) = (x + 4)(x -3) \\ x = - 4 \: \: \: or \: x = 3$

sum of zeroes =-b/a =-1/1= -1 =(-4+3)

product of zeroes =c/a =-12/1 =-12=(-4×3)