Question

find the zeroes of the quadratic polynomial:
p(y)=√3y² - 8y + 4√3​

Answer 1

Answer:

p(y)=√3y^2-8y+4√3

=√3y^2-6y-2y+4√3

=√3y(y-2√3)-2(y-2√3)

=(√3y-2)(y-2√3)

y=2/√3 , 2√3