Math, asked by akshatsinghsis, 1 month ago

Find the zeroes of the quadratic polynomial p(y) = 4√3y^2 +5y -2√3 and verify the relationship between the zeroes and their coefficients.

Answers

Answered by SeCrEtID2006
73

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ƓƖƔЄƝ :-

  • 4√3y^2 +5y -2√3

ƬƠ ƑƖƝƊ -

  • ȤЄƦƠЄƧ ƠƑ ƤƠԼƳƝƠMƖƛԼ

ƧƠԼƲƬƖƠƝ':-

  • 4√3y^2 +5y -2√3

  • 4√3y²+8y-3y-2√3

  • 4y(√3y +2) -√3(√3y+2)

  • (4y-√3)(√3+2)

hence zeroes are

  • 4y-√3=0

  •  \frac{√3}{4}  =y

and

  • √3y+2=0

  • y= \frac{-2}{√3}

\huge\fbox\color{red}ƔЄƦƖƑƳ-

━━━━━━━━❪❐❫━━━━━━━━

  • α+β= \frac{-b}{a}

  •  \frac{√3}{4}  + \frac{-2}{√3}  = \frac{-(5)}{4√3}

  •  \frac{-(5)}{4√3}  = \frac{-(5)}{4√3}

━━━━━━━━❪❐❫━━━━━━━━

  • αβ= \frac{c}{a}

  •  \frac{√3}{4}  ×  \frac{-2}{√3}  = \frac{-1}{2}

  •  \frac{-1}{2}  = \frac{-1}{2}

· · • • • ✤ • • • · ·· · • • • ✤ • • • · ·

Hence verified

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