Question

Find the zeroes of the quadratic polynomial t^2-15 and verify the relationship between their zeroes and the coefficient

Answer 1

hey here is ur answer ---;

t²-15= 0
t²= 15
t = root 15
alpha = - root 15

beeta = + root 15

Answer 2

$\textbf{\underline{\underline{According\:to\:the\:Question}}}$

t² - 15

★We can write it as :-

(t - √15)(t + √15)

★Now :-

(t - √15) = 0

t = √15

(t + √15) = 0

t = - √15

★Here we get two zeroes √15 and -√15

★Sum of zeroes :-

= α + β

= √15 + (-√15)

= √15 - √15

= 0

★Product of zeroes :-

= α × β

= √15 × (-√15)

= 15