Question

Find the zeroes of the quadratic
polynomial
$\sqrt{3x {}^{2} } - 8x + 4 \sqrt{3}$




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Answer 1

Solution:

Let p(x) =√3x²-8x+4√3

To find zeroes of p(x), we must take p(x) = 0,

√3x²-8x+4√3=0

Splitting the middle term,we get

=> √3x²-6x-2x+4√3=0

=> √3x(x-2√3)-2(x-2√3)=0

=> (x-2√3)(√3x-2)=0

=> x-2√3 = 0 or √3x-2 = 0

=> x = 2√3 or √3x = 2

=> x = 2√3 or x = 2/√3

Therefore,

2√3 , 2/√3 are two zeroes of

p(x)

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Answer 2

pls find the attached file.