Question

Find the zeroes of the quadratic polynomial the
x² + 8x + 16 and verify the relationship between the zero and the coefficient.
answer photo please ╥﹏╥​

Answer 1

Answer:

I hope the answer helps you

Answer 2

Answer:

Step-by-step explanation:

Let f(x) = $x^{2}$ ˗ 2x ˗ 8

            = $x^{2}$ ˗ 4x + 2x ˗ 8                                 (MIDDLE TERM)

            = x(x ˗ 4) + 2(x ˗ 4)

           = (x ˗ 4) (x + 2)

To find the zeroes, set f(x) = 0,

then either (x ˗ 4) = 0 or (x+2) = 0

                   ⇒ x = 4 or x = -2

Again, Sum of zeroes = (4 – 2) = 2 = 2/1 = -b/a =

                                      (-Coefficient of x)/(Coefficient of x2)

Product of zeroes = (4) (-2) = -8/1 = c/a

                                  ⇒ (Constant term)/( Coefficient of x2)

THANK U ... HOPE IT HELPS