Math, asked by Bhevna, 1 year ago

Find the zeroes of the quadratic polynomial with given number as the sum and the product of its zeroes respectively √2,1/3

Answers

Answered by rkp7480
2
x^2-root under 2+1/3
3x^2- 3 root under 2+1


rkp7480: make me brainliiest
Answered by Cutiepie93
26
Hello friends!!

Here is your answer :

For a quadratic polynomial ,

( x² - ( sum of Zeroes ) x + ( product of Zeroes )

Given

sum \:  \: of \:  \: zeroes \:  =  \sqrt{2}


 \\ product \:  \: of \:  \: zeroes \:   =   \frac{1}{3}


Quadratic polynomial is


 \\  {x}^{2}  - ( \sqrt{2} )x +  (\frac{1}{3} )



  \\ =  >  {x}^{2}  -  \sqrt{2} x +  \frac{1}{3}



 =  > 3 {x}^{2}  - 3 \sqrt{2}  + 1


Hope it helps you.. ^_^

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