Question

Find the zeroes of the quadratic polynomial x
2
-2x-8, and verify the

relationship between the zeroes and its coefficients.
urgenttttttttttttt

Answer 1

Answer and explanation:

$x {}^{2} - 2x - 8$

$= x {}^{2} + 2x - 4x - 8$

$= x(x + 2) - 4(x + 2)$

$= (x - 4)(x + 2)$

Hence, the roots of the polynomial are 4 and -2.

$4 + ( - 2) = \frac{ - (- 2)}{1} ( \frac{ - b}{a} ) = 2$

Hence, sum of the roots is -b/a.

$(4)( - 2) = \frac{ - 8}{1} ( \frac{c}{a}) = - 8$

Product of the roots is equal to c/a.

I hope this answer helps. :D

Product of the