Question

Find the zeroes of the quadratic polynomial x^2-36 and verify the relationship between the zeroes and the coefficients

Answer 1

Answer:

${x}^{2} - 36 = {(x)}^{2} - {(6)}^{2}$

$(x + 6)(x - 6)$

•°• x= 6 & -6

${x}^{2} - 0.x - 36$

$\alpha + \beta = 6 - 6 = 0$

$\alpha + \beta = \frac{ - b}{a}$

$= \frac{0}{1 } = 0$

$\alpha \beta = 6 \times ( - 6) = - 36$

$\alpha \beta = \frac{c}{a}$

$= \frac{ - 36}{1} = - 36$