Question

Find the zeroes of the Quadratic polynomial x^2 -5x+6 and verify the relationalship between the
zeroes & the coefficients.​

Answer 1

Answer:

x=3,2

Step-by-step explanation:

given that

=> x square-5x+6=0

=>x square-3x-2x+6=0

=>x(x-3)-2(x-3)=>0

here taking (x-3) as common then,

=>(x-3)(x-2)=0

then eqauating to 0 then,

x=2, or x=3.

OR it can be written in the formula method:

As we know that,

= -b+or-√b square-4ac/2a by substituting the value we get x=2or3