Find the zeroes of the Quadratic polynomial x^2 -5x+6 and verify the relationalship between the
zeroes & the coefficients.
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Answer:
x=3,2
Step-by-step explanation:
given that
=> x square-5x+6=0
=>x square-3x-2x+6=0
=>x(x-3)-2(x-3)=>0
here taking (x-3) as common then,
=>(x-3)(x-2)=0
then eqauating to 0 then,
x=2, or x=3.
OR it can be written in the formula method:
As we know that,
= -b+or-√b square-4ac/2a by substituting the value we get x=2or3
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