Question

Find the zeroes of the quadratic polynomial x^2 + 7x + 10 and verify the relationship b/w the zeroes and its co-efficients

Answer 1

Mark as brainliest....

hope it helps you

Answer 2

Answer:

x = -5 and -2

Step-by-step explanation:

We have been given the polynomial:-

x² + 7x + 10

To find its zeros equate it to zero.

x² + 7x + 10 = 0

Re-write it as:-

x² + 5x + 2x + 10 = 0

x(x+5) + 2(x+5) = 0

(x+5)(x+2) = 0

x = -5 and -2

Zeroes of the polynomial would be -5 and -2 !

1. Sum of zeros = $\dfrac{-b}{a}$

-5 + (-2) = $\dfrac{-(7)}{1}$

-7 = -7

2. Product of Zeros = $\dfrac{c}{a}$

(-5)(-2) = $\dfrac{10}{1}$

10 = 10

Verified !