Question

Find the zeroes of the quadratic polynomial x^2+7x+10 and verify the relationship between the zeroes and the coefficients. ​

Answer 1

Answer:

$x {}^{2} + 7x + 10$

$x {}^{2} + 5x + 2x + 10$

$x(x + 5) + 2(x + 5)$

$(x + 2)(x + 5)$

$x = - 2 \: and \: x = - 5$

$sum \: of \: zeros = - b \: by \: a$

$= - 7$

$product \: of \: zeros = c \: by \: a$

$= 10$

$verification$

$sum \: of \: zeros = - 5 + ( - 2) = - 7$

$product \: of \: zeros = - 5 \times - 2 = 10$

hope it will help you..

Answer 2

Answer:

x^2+7x+10

x^2+5x+2x+10

x(x+5) +2 (x+5)

(x+2) (x+5)