Question

find
the zeroes of the Quadratic polynomial x^2+ 99x + 127

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Answer 1

Answer:

a = 1, b = 99, c = 127. Thus x = −99−96.42 and x = −99+96.42. x = -1.3 and x = -97.7. Hence we got both the zeroes as negative, i.e. x = -1.3, -97.7.