Find the zeroes of the quadratic polynomial x + 7x + 10, and verify the relationship between zeroes
and its co - efficients.
Answers
CORRECT QUESTION.
Find the zeroes of the quadratic polynomial
x² + 7x + 10 = 0 and verify the relationship
between zeroes and it's coefficient.
Equation = x² + 7x + 10.
Sum of zeroes of quadratic equation
a + b = -b/a = -7/1
Products of zeroes of quadratic equation
ab = c/a = 10.
Verify.
x² + 7x + 10 = 0
Factories into middle term split.
→ x² + 5x + 2x + 10 = 0
→ x ( x + 5 ) + 2 ( x + 5 ) = 0
→ ( x + 2 ) ( x + 5 ) = 0
→ x = -2 and x = -5.
Sum = -2 + (-5) = -7.
Products = (-2) X (-5) = 10
HENCE VERIFIED.
- This question says that there is a quadratic polynomial . The equation is x² + 7x + 10 = 0. Afterwards it ask us to u verify the relationship between zeroes and its co - efficients.
Find the zeroes of the quadratic polynomial x² + 7x + 10 = 0 and verify the relationship between zeroes and its co - efficients.
- Equation = x² + 7x + 10 = 0
- Verify the relationship between zeroes and its co - efficients.
Note : Kindly see the full answer to get it properly.
- Sum = -7
- Product = 10
- To solve this question firstly we have to see the Sum of zeros of the quadratic polynomial. Afterwards product of zeros of the quadratic polynomial. Afterthat putting the values we get value of x = -5 and x = -2. Afterwards substituting the value of x finding sum and product. We gry our result very easily.
According to the question let's carry on
Sum of zeros of the quadratic polynomial -
- a + b = -b / a = -7 / 1
Product of zeros of the quadratic polynomial -
- a × b (ab) = c / a = 10
➝ x² + 7x + 10 = 0.
Putting the values we get the following results.
➝ x² + 5x + 2x + 10 = 2
➝ x(x+5) + 2(x+5) = 0
➝ (x + 2) (x + 5) = 0
➝ x = -5 and x = -2
- Sum = -2 + (-5)
➝ Sum = -2 -5
➝ Sum = -7
- Product = (-2) × (-5)
➝ Product = 2 × 5
➝ Product = 10
Hence, verified ✓