Question

Find the zeroes of the quadratic polynomial x(square) - 13x+6
and verify the relation between the zeroes and its coefficients ​

Answer 1

Step-by-step explanation:

x^2-13x+6

$\alpha + \beta = - ( - 13) + \div 1$

$\alpha + \beta = 13$

$\alpha \times \beta = 6 \div 1$

$\alpha \times \beta = 6$