find the zeroes of the quadratic polynomial x square+3x-10 and verify the relation between its zeroes and coefficients.
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p(x)= x²+3x-10
x²+5x-2x-10
x(x+5) -2(x+5)
(x-2)(x+5)
x-2=0. / x+5=0
x=2 / x= -5
zeroes of px are 2&-5
sum = 2+(-5)=-3
-b/a= -3/1 = -3
product= 2×(-5)= -10
c/a= -10/1=-10
hope it helps
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x²+5x-2x-10
x(x+5) -2(x+5)
(x-2)(x+5)
x-2=0. / x+5=0
x=2 / x= -5
zeroes of px are 2&-5
sum = 2+(-5)=-3
-b/a= -3/1 = -3
product= 2×(-5)= -10
c/a= -10/1=-10
hope it helps
mark as brainliest
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