Question

Find the zeroes of the quadratic polynomial x²+2x+10,and verify the relationship between the zeroes and the coefficients​

Answer 1

Answer:

Step-by-step explanation:

x²+2x+10

=> a=1 , b=2 , c=10

by Quadratic Formula:

x = -b ±  $\sqrt{b^{2} - 4ac\frac}$ / 2a

Therefore:

-(2) ± $\sqrt{2^{2}-4*1*10 }$ / 2*1

=> -2 ± $\sqrt{-36}$ / 2

The Discriminant [b²- 4ac] is negative, which implies that there is no real solution to the root.