Question

Find the zeroes of the quadratic polynomial:
x2 — 2x + 3

Answer 1

Answer:

x2-2x+3=0

x2+x-3x+3=0

x(x+1)-3(x+1)=0

x=3 or x=-1

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Value\:of\:x=1\pm\sqrt{2}\iota}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies {x}^{2} - 2x + 3 = 0 \\ \\ \red{\underline \bold{To \: Find :}} \\ \tt: \implies Value \: of \: x = ?$

• According to given question :

$\tt \circ \: a = 1 \\ \\ \tt \circ \: b = - 2 \\ \\ \tt \circ \: c = 3$

$\bold{As \: we \: know \: that} \\ \tt: \implies x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ \tt: \implies x = \frac{ - (-2) \pm \sqrt{ {(-2)}^{2} - 4 \times 1 \times 3 } }{2 \times 1}$

$\tt : \implies x = \frac{2 \pm \sqrt{4 - 12} }{2} \\ \\ \tt : \implies x = \frac{2 \pm \sqrt{ - 8} }{2} \\ \\ \tt : \implies x = \frac{2 \pm \sqrt{8} \iota }{2} \\\\ \green{\tt:\implies x = 1\pm \sqrt{2}\iota}$