Question

find the zeroes of the quadratic polynomial x²-2x-8 and verify the relationship between the zeroes and the coefficient​

Answer 1

Answer:

Step-by-step explanation:

x² - 2x - 8 = 0

D = (- 2)² - 4×1×(- 8) = 4 + 32 = 36 = 6²

$x_{12}$ = [- (- 2) ± √36] / 2 = (2 ± 6) / 2

$x_{1}$ = 4 and $x_{2}$ = - 2

$x_{1}$ × $x_{2}$ = $\frac{c}{a}$ = 4×(- 2) = - 8

$x_{1}$ + $x_{2}$ = $-\frac{b}{a}$ = - ( - 2 + 4) = - 2