Find the zeroes of the quadratic polynomial : x2 – 2x – 8 and verify the relationship between
the zeroes and the coefficients.
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f(x) = x^2 - 2x - 8 f(x) = x^2 - 4x + 2x - 8 f(x) = x(x - 4) + 2(x - 4)] f(x) = (x - 4)(x + 2) Zeros of f(x) are given by f(x) = 0 x^2 - 2x - 8 = 0 (x - ... More
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