Question

find the zeroes of the quadratic polynomial x²-2x-8 and verify the relationship between the zeroes and cofficient​

Answer 1

x^2-2x-8=0

x^2+2x-4x-8=0

x(x+2)-4(x+2)=0

(x+2)(x-4)=0

x+2=0. x-4=0

x=-2. x=4

alpha=-2. beta=-4

sum of the zeroes= alpha+beta=-b/a

-2+4=-(-2)/1

2=2

product of the zeroes= alpha×beta=c/a

-2×+4=-8/1

-8=-8