Question

find the zeroes of the quadratic polynomial x²(√3+1)x+√3 and verify the relationship between the zeroes and the coefficients

Answer 1

HEY DEAR....
HERE'S YOUR ANSWER.
• x²-(√3+1)x+√3.
• x²-x-√3x+√3.
• x(x-1)-√3(x-1).
• (x-1) ; (x-√3).
• therefore x = 1 ; +√3.
♦SOZ : -b/a.
= -[-(√3+1)]/1
= √3+1.
♦ x1+x2 = √3+1.
♦POZ : c/a.
= √3/1.
= √3.
♦ x1(x2) = (√3)(1).
= √3.
HENCE PROVED.
I HOPE YOU FIND IT HELPFUL.
YOUR CARING FRIEND.
#Hermione. ;-)

Answer 2

Step-by-step explanation:

=x^2-(√3+1)x+√3

=x^2-√3-x+√3

=x(x-√3)-1(x-√3)

=(x-1)(x-√3)

alpha=1 and beta=√3