Find the zeroes of the quadratic polynomial x²+4√2x+6
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x² + 4√2x + 6 = 0
x² + 4√2x = - 6
x² + 4√2x + (2√2)² = (2√2)² - 6
(x + 2√2)² = 8 - 6
(x + 2√2)² = 2
x + 2√2 = ±√2
x =√2- 2√2
raj1823:
thank you so much
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