Question

Find the zeroes of the quadratic polynomial x²-4x-32 and verify the relationship between the zeroes and the coefficients​

Answer 1

Step-by-step explanation:

x2-4x-32

x2-8x+4x-32

x(x-8)+4(x-8)

Therefore, (x-8) and (x+4)=0

x-8=0 , x+4=0

Therefore x=8 and x=-4 are the zeroes

Now,

Sum Of Zeroes = -b/a

(8)+(-4)

8-4 = 4

-(-4)/1 = -coffieceint x/coffiecient of x2

Product of zeroes = c/a

(8) x (-4)

-32/1 = c/a = Constant Term/coffiecient of x2

MARK ME AS A BRAINLIEST