Question

Find the zeroes of the quadratic polynomial x2 + 5x + 6 and verify the relationship

between the zeroes and its coefficients.
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Answer 1

Given - x²+5x+6

x²+(3+2)x+6

x²+3x+2x+6

x(x+3)+2(x+3)

(x+3)(x+2)

so zero are -3,-2

So , sum of zeros are =-3+(-2)=-5 = - coefficient of x/ coefficient of X2

Product of zero = (-3)(-2) = 6 = constant term / coefficient of x²

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Answer 2

Step-by-step explanation:

x2+5x+6

x2+3x+2x+6

x{x+3}+2{x+3}

{x+2}{x+3}

comparing with zero

x+2=0,x+3=0

x=-2,x=-3

Verification

1)alpha+beta=-b/a

-2+{-3}=-5

-5=-5

2)alpha×beta=c/a

-2×(-3)=6

6=6

LHS=RHS

HENCE VERIFIED

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