Question

Find the zeroes of the quadratic polynomial x2+7x+10

Answer 1

SOLUTION ☺️

$= > {x}^{2} - 7x + 10 = 0\\ = > {x}^{2} - 5x - 2x + 10 = 0 \\ = > x(x - 5) - 2(x - 5) = 0\\ = > (x - 5) = 0 \: \: \: or \: \: \: \: (x - 2) = 0 \\ = > x = 5 \: \: an \: \: x = 2 \\ \\ now \\ = > sum \: of \: zeroes = - \frac{b}{a} = - \frac{ - 7}{1} = 7 \\ \\ = > product \: of \: zeroes = \frac{c}{a} = \frac{10}{1} = 10$

HOPE it helps ✔️

Answer 2

x2 + 7x + 10 = (x + 2)(x + 5)

So, the value of x2 + 7x + 10 is zero when x + 2 = 0 or x + 5 = 0

Therefore, the zeroes of x2 + 7x + 10 are –2 and –5.

Sum of zeroes = -7 = –(Coefficient of x) / (Coefficient of x2)

Product of zeroes = 10 = Constant term / Coefficient of x2