Question

find the zeroes of the
quadratic polynomial
x² + 7x +10.​

Answer 1

Answer :-

• - 2 and - 5

Given :-

• A quadratic equation x² + 7x + 10

To Find :-

• Zeroes of the quadratic equation.

Solution :-

x² + 7x + 10

[ Split the middle term ]

→ x² + 5x + 2x + 10

→ x (x + 5) + 2 (x + 5)

→ (x + 2) (x + 5)

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• x + 2 = 0

→ x = 0 - 2

→ x = - 2

• x + 5 = 0

→ x = 0 - 5

→ x = - 5

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Hence, the zeroes of the polynomial are - 2 and - 5 respectively.

Answer 2

Answer :

• We have to find the zeroes of the quadratic polynomial x² + 7x + 10 .

★ We can do this by middle term split

$\implies \sf x²\:+\:7x\:+\:10$

$\implies \sf x²\:+\:5x\:+\:2x\:+\:10$

$\implies \sf x(x\:+\:5)\:+\:2(x\:+\:5)$

$\implies \sf (x\:+\:5)(x\:+\:2)$

• Now , equating to zero for finding zeroes of polynomial .

$\implies \sf x\:+\:5\:=\:0$

$\implies \sf x\:=\:-\:5$

$\implies \sf x\:+\:2\:=\:0$

$\implies \sf x\:=\:-\:2$

• Zeroes are -5 and -2 .

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