find the zeroes of the quadratic polynomial x2+7x+10 and verify the relationship between the zeroes and the cofficient.
Answers
Solution :
The quadratic polynomial x² + 7x + 10
The zeroes and verify the relationship between the zeroes and the coefficient.
We have p(x) = x² + 7x + 10
Zero of the polynomial is p(x) = 0
So;
∴ The α = -2 and β = -5 are the zeroes of the polynomial.
As the given quadratic polynomial as we compared with ax²+bx+c=0
- a = 1
- b = 7
- c = 10
So;
Thus;
Relationship between zeroes and coefficient is verified .
Solution :-
→ x² + 7x + 10 = 0
→ x² + 2x + 5x + 10 = 0
→ x(x + 2) + 5(x + 2) = 0
→ (x + 2)(x + 5) = 0
Putting Both Equal to zero now,
→ x + 2 = 0
→ x = (-2).
&
→ x + 5 = 0
→ x = (-5) .
_____________________
Now, First Relation is :-
→ Sum of Zeros = - (coefficient of x) /(coefficient of x²)
Putting both values ,
→ (-2) + (-5) = -(7)/1
→ (-7) = (-7) ✪✪ Hence Verified. ✪✪
Second Relation :-
→ Product Of Zeros = Constant Term / (coefficient of x²)
Putting both Values ,
→ (-2) * (-5) = (10) / 1