find the zeroes of the quadratic polynomial x²+ 7x+10 and verify the relationship between the zeroes and the cofficient
Answers
Answer:
Explanation:
Given :
- Quadratic polynomial, x² + 7x + 10.
To Find :
- Verify the relationship between the zeroes and the cofficient's.
Solution :
Given that, quadratic polynomial, x² + 7x + 10.
On comparing with, ax² + bx + c, We get;
=> a = 1 , b = 7 , c = 10
Now, find zeroes of given quadratic polynomial,
x² + 7x + 10
=> x² + 5x + 2x + 10
=> x(x + 5) + 2(x + 5)
=> (x + 2) (x + 5)
=> α = -2 & β = -5
• Sum of zeroes = -b/a
=> α + β = -b/a
=> -2 + (-5) = -(7)/1
=> -7 = -7
• Product of zeroes = c/a
=> α × β = c/a
=> -2 × -5 = 10/1
=> 10 = 10
- Hence, Relationship is verified!!
Answer :-
Given :
- Quadratic polynomial, x² + 7x + 10.
To Find :
- Verify the relationship between the zeroes and the cofficient's.
Solution :
Given that, quadratic polynomial, x² + 7x + 10.
On comparing with, ax² + bx + c, We get;
=> a = 1 , b = 7 , c = 10
Now, find zeroes of given quadratic polynomial,
Now, find zeroes of given quadratic polynomial,x² + 7x + 10
=> x² + 5x + 2x + 10
=> x(x + 5) + 2(x + 5)
=> (x + 2) (x + 5)
=> α = -2 & β = -5
• Sum of zeroes = -b/a
=> α + β = -b/a
=> -2 + (-5) = -(7)/1
=> -7 = -7
• Product of zeroes = c/a
=> α × β = c/a
=> -2 × -5 = 10/1
=> 10 = 10
Hence, Relationship is verified!!