Math, asked by kaluramjat67400, 2 months ago

find the zeroes of the quadratic polynomial x²+ 7x+10 and verify the relationship between the zeroes and the cofficient​

Answers

Answered by Anonymous
5

Answer:

Explanation:

Given :

  • Quadratic polynomial, + 7x + 10.

To Find :

  • Verify the relationship between the zeroes and the cofficient's.

Solution :

Given that, quadratic polynomial, + 7x + 10.

On comparing with, ax² + bx + c, We get;

=> a = 1 , b = 7 , c = 10

Now, find zeroes of given quadratic polynomial,

+ 7x + 10

=> x² + 5x + 2x + 10

=> x(x + 5) + 2(x + 5)

=> (x + 2) (x + 5)

=> α = -2 & β = -5

Sum of zeroes = -b/a

=> α + β = -b/a

=> -2 + (-5) = -(7)/1

=> -7 = -7

Product of zeroes = c/a

=> α × β = c/a

=> -2 × -5 = 10/1

=> 10 = 10

  • Hence, Relationship is verified!!

Answered by Anonymous
7

Answer :-

Given :

  • Quadratic polynomial, x² + 7x + 10.

To Find :

  • Verify the relationship between the zeroes and the cofficient's.

Solution :

Given that, quadratic polynomial, x² + 7x + 10.

On comparing with, ax² + bx + c, We get;

=> a = 1 , b = 7 , c = 10

Now, find zeroes of given quadratic polynomial,

Now, find zeroes of given quadratic polynomial,x² + 7x + 10

=> x² + 5x + 2x + 10

=> x(x + 5) + 2(x + 5)

=> (x + 2) (x + 5)

=> α = -2 & β = -5

Sum of zeroes = -b/a

=> α + β = -b/a

=> -2 + (-5) = -(7)/1

=> -7 = -7

Product of zeroes = c/a

=> α × β = c/a

=> -2 × -5 = 10/1

=> 10 = 10

Hence, Relationship is verified!!

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