Find the zeroes of the quadratic polynomial x2+7x+ 10 and verify relationsp between the zeroes and the coefficient
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Given Polynomial is x^2+7x+10
= x^2+5x+2x+10
= x(x+5)+2(x+5)
= (x+2)(x+5)
Either x+2=0 or x+5=0
=> x+2=0 or, x+5=0
=> x= -2 or x= -5
-------------------------------------
sum of zeroes= -b/a= -(-2-5)= 7
products of zeroes= c/a= (-5*-2)= 10
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Given Polynomial is x^2+7x+10
= x^2+5x+2x+10
= x(x+5)+2(x+5)
= (x+2)(x+5)
Either x+2=0 or x+5=0
=> x+2=0 or, x+5=0
=> x= -2 or x= -5
-------------------------------------
sum of zeroes= -b/a= -(-2-5)= 7
products of zeroes= c/a= (-5*-2)= 10
______________________
hope u likd it✌✌
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