Find the zeroes of the quadratic polynomial x2+7x+12
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Answer:
Answer x is equal to -3, -4
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x² + 7x + 12
= x² + 3x + 4x + 12
= x(x + 3) + 4(x + 3)
= (x + 3)(x + 4)
To find the zeroes,
x + 3 = 0 => x = -3
or, x + 4 = 0 => x = -4
Thus, -3 and -4 are the zeroes of the given polynomial.
Hope, it'll help you.....
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