Question

find the zeroes of the quadratic polynomial x2+7x+12 and verify the relation between the two zeroes and its coefficients?

Answer 1

Hai friend,
here is your answer,
The polynomial is x²+7x+12

a=1,b=7,c=12
Factors of x²+7x+12

=x²+4x+3x+12
=x(x+4)+3(x+4)
=(x+4)(x+3)

Zeroes of the polynomial

x²+7x+12 =0

(x+4)(x+3)=0

x= -4,-3

ZEROES = -4, -3

SUM OF ROOTS = -4-3=-b/a=-7/1
=> -7=-7

PRODUCT OF ROOTS= -4*-3=c/a

=> 12=12


hope helped

Answer 2

given polynomial x²+7x+12

x²+4x+3x+12

x(x+4)+3(x+4)

(x+3)(x+4)

-3,-4 are the zeros


sum of zeros=-7=-b/a=-7

product of zeros =12=c/a=12

hence verified.



I hope this will help u ;)