Find the zeroes of the quadratic polynomial x²-7x+12 and verify the relationship between the zeroes and the coefficients of the polynomial ?
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Let f(x)=x
2
+7x+12
f(x)=x
2
+4x+3x+12
f(x)=x(x+4)+3(x+4)
f(X)=(x+4)(x+3)
To find the zeros , Let f(x)=0 , then
either (x+4)=0 or (x+3)=0
x=−4 or x=−3
again
sum of zeros =(−4−3)=−7=
1
−7
=
a
−b
=
(coefficient of x
2
)
(−coefficient of x)
product of zeros =−4×−3=12=
1
12
=
a
c
=
coefficient of x
2
constant term
Step-by-step explanation:
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