Question

Find the zeroes of the quadratic polynomial x²-7x+12 and verify the relationship between the zeroes and the coefficients of the polynomial ?​

Answer 1

Answer:

Answer

Let f(x)=x  

2

+7x+12

f(x)=x  

2

+4x+3x+12

f(x)=x(x+4)+3(x+4)

f(X)=(x+4)(x+3)

To find the zeros , Let f(x)=0  , then

either (x+4)=0 or  (x+3)=0

 

x=−4 or x=−3

again

sum of zeros =(−4−3)=−7=  

1

−7

​  

=  

a

−b

​  

=  

(coefficient of x  

2

)

(−coefficient of x)

​  

 

product of zeros =−4×−3=12=  

1

12

​  

=  

a

c

​  

=  

coefficient of x  

2

 

constant term

​  

Step-by-step explanation: