Question

. Find the zeroes of the quadratic polynomial x2 - 7x- 18 and verify the
relationship between the zeroes and the coefficients.​

Answer 1

Answer:

p(x)=x^2-7x-18. 18=9×2

Step-by-step explanation:

=x^2+2x-9x-18

=x(x+2)-9(x+2)

=(x-9)(x+2)

x=9or x=-2 are the zeros of p(x)

now ,

x=9& y =-2. [x for alpha & y for beta]

relationship between the zeros and coefficient

sum of zero=x+y=-b/a

9+(-2)=7=-7/1

product of zeros =xy=c/a

9(-2)= -18= -18/1

Hence proved

Answer 2

Answer:

Step-by-step explanation:

=x^2+2x-9x-18

=x(x+2)-9(x+2)

=(x-9)(x+2)

x=9or x=-2 are the zeros of p(x)

now ,

x=9& y =-2. [x for alpha & y for beta]

relationship between the zeros and coefficient

sum of zero=x+y=-b/a

9+(-2)=7=-7/1

product of zeros =xy=c/a

9(-2)= -18= -18/1