Question

find the zeroes of the quadratic polynomial X2+7x-30 & varify the relationship between the zeroes & the coefficients
(please give me correct answer and fast I need help please)​

Answer 1

Answer:

pls answer of my question in my profile

Step-by-step explanation:

The lithosphere is the solid, outer part of the Earth. The lithosphere includes the brittle upper portion of the mantle and the crust, the outermost layers of Earth's structure. It is bounded by the atmosphere above and the asthenosphere

Answer 2

S O L U T I O N :

We have quadratic polynomial p(x) = x² + 7x - 30 & zero of the polynomial p(x) = 0

$\underline{\underline{\tt{Using\:\:by\:\:factorisation\:\:method\::}}}$

→ x² + 7x - 30 = 0

→ x² + 10x - 3x - 30 = 0

→ x(x + 10) - 3(x + 10) = 0

→ (x + 10) (x - 3) = 0

→ x + 10 = 0  Or  x - 3 = 0

→ x = -10  Or  x = 3

∴ α = -10 & β = 3 are the two zeroes of the given polynomials .

As we know that given quadratic polynomial compared with ax² + bx + c;

• a = 1
• b = 7
• c = -30

Now,

$\underline{\mathcal{SUM\:OF\:THE\:ZEROES\::}}$

$\mapsto\tt{\alpha +\beta = \dfrac{-b}{a} =\bigg\lgroup\dfrac{Coefficient\:of\:x}{Coefficient\:of\:x^{2}}\bigg\rgroup }$

$\mapsto\tt{-10+3 = \dfrac{-7}{1} }$

$\mapsto\bf{-7= -7}$

$\underline{\mathcal{PRODUCT\:OF\:THE\:ZEROES\::}}$

$\mapsto\tt{\alpha \times \beta = \dfrac{c}{a} =\bigg\lgroup\dfrac{Constant\:term}{Coefficient\:of\:x^{2}}\bigg\rgroup }$

$\mapsto\tt{-10\times 3 = \dfrac{-30}{1} }$

$\mapsto\bf{-30= -30}$

Thus,

The relationship between zeroes & coefficient are verified .