Find the zeroes of the quadratic polynomial x2 + 7x + 6 and verify the relationship between the zeroes and the coefficients.
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Answer:
X²-7X-6=0
X²-7X-6+(7/2)²-(7/2)²=0
[X²-7X+(7/2)²]-6-(7/2)²=0
X²-7X+(7/2)²=6+(7/2)²
(X-7/2)²=73/4
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